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Will crown best answer

Will crown best answer-example-1
User Iameli
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1 Answer

4 votes

Answer:

0.7143

Explanation:

we shall analyze the table given. we are to find the probability that the chosen student is male, or has a grade of A. this means the union of these two probabilities.

let the event that the student is a male be A, and the event that the student has an A be B.

recall the formula:


P(A\cup B)=P(A)+P(B)-P(A\cap B)

where
P(A\cup B) means A or B, and
P(A\cap B) means A and B.

here, we need to find
P(A), P(B), P(A\cap B). lets find them one by one.


P(A) here is the probability that the chosen student is male. of the 49 students, 20 are male. So,
P(A)=(20)/(49).

next,
P(B) is the probability that the chosen student has an A. of the 49 students, again 20 have an A. so,
P(B)=(20)/(49).

lastly,
P(A\cap B) is the probability that the chosen student is both male and has an A. of the 49 students, 5 of them satisfy this. hence,
P(A\cap B)=(5)/(49).

finally, we can calculate the union probability, being:


P(A\cup B)=(20)/(49)+(20)/(49)-(5)/(49)=(35)/(49)=(5)/(7), equal to 0.7143 to 4 decimal places.

User Shernett
by
7.2k points