Question

1. 2х^2 * 3x^3y * 3x^3y=1. 2х^2 * 3x^3*y * 3x^3*y=

Answer 1

Multiplication of exponential expressions

Given the expressions

`\begin{gathered} (A).2x^2\cdot3x^3\cdot y\cdot3x^3\cdot y= \\ (B).2x^2\cdot3x^(3y)\cdot3x^(3y)= \end{gathered}`

First: we group and multiply the numbers

`\begin{gathered} (A).2x^2\cdot3x^3\cdot y\cdot3x^3\cdot y=(2\cdot3\cdot3)\cdot x^2\cdot x^3\cdot y\cdot x^3\cdot y=18x^2\cdot x^3\cdot y\cdot x^3\cdot y \\ (B).2x^2\cdot3x^(3y)\cdot3x^(3y)=(2\cdot3\cdot3)x^2\cdot x^(3y)\cdot x^(3y)=18x^2\cdot x^(3y)\cdot x^(3y) \end{gathered}`

Now we have the expressions

`\begin{gathered} (A).18x^2\cdot x^3\cdot y\cdot x^3\cdot y \\ (B).18x^2\cdot x^(3y)\cdot x^(3y) \end{gathered}`

Second: we multiply the expressionswith the same base adding its exponents

`\begin{gathered} (A).18x^(2+3+3)\cdot y^(1+1)=18x^8y^2 \\ (B).18x^(2+3y+3y)=18x^(6y+2) \end{gathered}`