Question

How many grams of NaOH are produced when 3.20g of o2 are formed

Answer 1

The mass of NaOH produced when 3.20 g of oxygen are formed from the reaction is 16 g

How to calculate the mass of NaOH produced?

First, we shall calculate the mass of sodium peroxide, Na₂O₂ needed to form 3.20 g of oxygen. Details below:

`2Na_2O_2(s)\ +\ 2H_2O(l) \rightarrow O_2(g)\ +\ 4NaOH(aq)`

• Molar mass of Na₂O₂ = 78 g/mol
• Reacting mass of Na₂O₂ from equation = 2 × 78 = 156 g
• Molar mass of O₂ = 32 g/mol
• Mass of O₂ produced from the balanced equation = 1 × 32 = 32 g
• Mass of O₂ produced from reaction = 3.20 g
• Mass of Na₂O₂ needed =?

32 g of O₂ were produced from 156 g of Na₂O₂

Therefore,

3.20 g of O₂ will be produce from =
`(3.2\ *\ 156)/(32)` = 15.6 g of Na₂O₂

Now, we shall obtain the mass of NaOH produced from the reaction. Details below:

`2Na_2O_2(s)\ +\ 2H_2O(l) \rightarrow O_2(g)\ +\ 4NaOH(aq)`

• Molar mass of Na₂O₂ = 78 g/mol
• Reacting mass of Na₂O₂ from equation = 2 × 78 = 156 g
• Molar mass of NaOH = 40 g/mol
• Mass of NaOH produced from the equation = 4 × 40 = 160 g
• Mass of Na₂O₂ that reacted = 15.6 g
• Mass of NaOH produced =?

From the balanced equation above,

156 g of Na₂O₂ reacted to produce 160 g of NaOH

Therefore,

15.6 g of Na₂O₂ will react to produce =
`(15.6\ *\ 160)/(156)` = 16 g of NaOH

Therefore, the mass of NaOH produced is 16 g

Complete question:

Oxygen is produced by the reaction of sodium peroxide and water.

2Na2O2(s) + 2H2O(l) ---> O2(g) + 4NaOH(aq)

How many grams of NaOH are produced when 3.20 g of O2 is formed?