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If a golf ball is hit at an angle of 15 degrees and a velocity of 50 m/s, how high will the golf ball travel?

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Final answer:

To find the maximum height reached by the golf ball, calculate the vertical component of the initial velocity and then plug it into the equation for maximum height in projectile motion.

Step-by-step explanation:

To calculate how high a golf ball hit at an angle of 15 degrees with a velocity of 50 m/s will travel, we will use the equations of projectile motion. The maximum height of a projectile is determined using the vertical component of the initial velocity, which can be found by Vy = V * sin(θ), where V is the initial velocity and θ is the launch angle. Using this, the vertical velocity is Vy = 50 m/s * sin(15°).

Once we have the vertical component of the velocity, we can use the formula for the maximum height H = Vy² / (2g), where g is the acceleration due to gravity (approximately 9.81 m/s²). Plugging in the numbers, we get H = (50 m/s * sin(15°))² / (2 * 9.81 m/s²).

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