The largest angle of the triangle TUV is 83.59 degrees
Finding the largest angle of the triangle TUV
From the question, we have the following parameters that can be used in our computation:
The triangle TUV
Assuming that s is a positive number, we have the following equation
a² = b² + c² - 2bccos(A)
Where
A is the angle opposte the longest side
Using the above as a guide, we have the following:
39² = 37² + 20² - 2 * 37 * 30 * cos(A)
This gives
39² - (37² + 20²) = - 2 * 37 * 30 * cos(A)
-248 = -2220cos(A)
This gives
cos(A) = 0.1117
Evaluate
A = 83.59
Hence, the largest angle of the triangle TUV is 83.59 degrees