In this question, we have to find the pH of 4 solutions with the given OH- concentration, and in order to do that, we have to find the pOH first, and then we can find the pH, the formula for pOH is the same as pH:
pOH = -log [OH-]
Solution 1:
pOH = -log [1.0*10^-2]
pOH = 2
pH + pOH = 14
pH = 14 - 2
pH = 12, this is a BASIC solution
Solution 2:
pOH = -log [1.0*10^-11]
pOH = 11
pH + pOH = 14
pH = 14 - 11
pH = 3, this is an ACIDIC solution
Solution 3:
pOH = -log [3.5*10^-2]
pOH = 1.45
pH + pOH = 14
pH = 14 - 1.45
pH = 12.55, this is a BASIC solution
Solution 4:
pOH = -log [4.4*10^-11]
pOH = 10.36
pH + pOH = 14
pH = 14 - 10.36
pH = 3.64, this is an ACIDIC solution