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Find a+b,2a+3b,∣a∣, and ∣a−b∣. a=51+1,b=1−31 a+b= 2a+3b=

User Adrilz
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1 Answer

5 votes

Final answer:

Unable to perform calculations due to incorrectly formatted and incomplete values of a and b in the question. The concepts needed to find a + b, 2a + 3b, |a|, and |a - b| are explained, but actual calculations cannot be completed without correct numerical values.

Step-by-step explanation:

To solve for a + b, 2a + 3b, |a|, and |a - b|, we first need to identify the values of a and b given in the question. However, the given values of a and b, being a=51+1 and b=1−31, appear to be incorrectly formatted and incomplete, thus preventing us from providing a numerical solution. Without the correct values for a and b, we can't proceed with calculations. It's worth noting that:

  • For the sum a + b, we would simply add the two values.
  • To calculate 2a + 3b, we would double the value of a and triple the value of b, then add the results together.
  • The absolute value |a| represents the non-negative value of a.
  • Lastly, |a - b| refers to the absolute value of the difference between a and b, which is also always non-negative.

If we had the correct numerical values for a and b, we would apply these principles to find each of the desired results.

User Kyle Xie
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