Question

Which equation does the graph of the systems of equations solve? (1 point) Quadratic graph opening down and quadratic graph opening up. They intersect at 2, negative 1 and negative 1, 2. x2 − 2x − 1 = −x2 + 3 x2 − 2x + 3 = x2 − x + 1 −x2 − 2x + 2 = 2x2 − x − 2 −x2 − 2x + 1 = 2x2 − x + 2

Answer 1

The equation that the graph of the system of equations solves is
`\(x^2 - 2x - 1 = -x^2 + 3\)`.

The given system of equations describes two quadratic functions with graphs that intersect at the points (2, -1) and (-1, 2).

To find the equation representing this intersection, you can set the two quadratic expressions equal to each other. Among the provided options,
`\(x^2 - 2x - 1 = -x^2 + 3\)` is the correct equation.

This equation is derived by setting the two quadratic expressions equal to each other and simplifying. It represents the points of intersection for the graphs of the given quadratic functions.