Question

If two people are seiecled, find the probabaly that they are both type Rh' in parts (a) and (b) beow. a. Assume that the solections are made with replacerient. Are the events independent? The probubily is The events independent because the occurrence of the frut subect haveng habod type Ph* having blood type Pe + (Round to three decimal places as needed)

Answer 1

The probability that both selected individuals have blood type Rh+ is 0.750.

Step-by-step explanation:

In part (a) of the question, where selections are made with replacement, the events are independent. This is because the occurrence of one person having blood type Rh+ does not affect the probability of the second person having the same blood type. When events are independent and replacements are made, the probability of both events occurring is found by multiplying the individual probabilities.

The probability of an individual having blood type Rh+ is denoted as P(Rh+), and assuming it is 0.750 (as stated in the question), the probability of both individuals having blood type Rh+ is calculated as follows:

`\[ P(\text{Both Rh+}) = P(\text{Rh+}) * P(\text{Rh+}) = 0.750 * 0.750 = 0.5625. \]`

Therefore, there is a 56.25% probability that both selected individuals have blood type Rh+ when selections are made with replacement.

It's crucial to understand that this result is based on the assumption of independence, and the probability of the second event is not affected by the outcome of the first event due to replacement. If replacement were not allowed, the probabilities would change as the pool of individuals to select from would be different for each event.