Question

If a ball is dropped from a bridge that is 36.4 meters high, how long will it take until the ball hits the ground below the bridge?

Answer 1

2.72 sec

Step-by-step explanation

Step 1

to solve this we need to use the formula

`h=v_0t+(1)/(2)gt^2`

let

`\begin{gathered} v_0=0 \\ h=36.4\text{ m} \\ g=9.8\text{ }\frac{\text{m}}{s^2} \\ t=\text{ unknown= t} \end{gathered}`

replace

`\begin{gathered} h=v_0t+(1)/(2)gt^2 \\ 36.4=0\cdot t+(1)/(2)(9.8\text{ }(m)/(s^2))t^2 \\ 36.4=+(4.9(m)/(s^2))t^2 \\ \text{divide both sides by 4.9} \\ (36.4)/(4.9)=t^2 \\ t=\sqrt[]{7.42} \\ t=2.72 \end{gathered}`

therefore, the answer is

2.72 sec

I hope this helps you