Question

A force in the +y direction applied at the point x= 2.3m, y= 1.4m gives rise to a torque of x=57Nm about the origin. Find the magnitude of the force.

Answer 1

The magnitude of the force is approximately 23.86 N.

Step-by-step explanation:

To find the magnitude of the force, we can use the formula for torque: torque = r x F, where r is the position vector and F is the force vector. In this case, the torque is given as 57 Nm and the position vector is (2.3, 1.4). Solving for F, we have |F| = torque / |r| = 57 Nm / √(2.3^2 + 1.4^2) = 57 Nm / √(5.29 + 1.96) = 57 Nm / √7.25 ≈ 23.86 N. Therefore, the magnitude of the force is approximately 23.86 N.