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a wooden ring whose mean diameter is 16.0 cm is wound with a closely spaced toroidal winding of 650 turns. compute the magnitude of the magnetic field at the center of the cross section of the windings when the current in the winding

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The magnitude of the magnetic field is 0.017 T.

The magnitude of the magnetic field at the center of the cross section of the windings can be found using the formula for the magnetic field inside a solenoid. The formula is given by B = μ0 * N * I / L, where μ0 is the permeability of free space, N is the number of turns in the winding, I is the current through the winding, and L is the length of the solenoid. In this case, the mean diameter of the wooden ring is 16.0 cm, so the length of the solenoid is equal to the circumference of the ring, which is π * 16.0 cm. Plugging in the values, we get B = (4π * 10^-7 T*m/A) * 575 * 0.660 A / (16.0 cm * π) = 0.017 T.

The complete question is- A wooden ring whose mean diameter is 16.0 cm is wound with a closely spaced toroidal winding of 575 turns.

Part A

Compute the magnitude of the magnetic field at the center of the cross section of the windings when the current in the windings is 0.660 A .

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