Question

For a certain metal, b is equal to v0 and electrons come out with a maximum velocity of 4×10 6 meters per second. If the value of p is equal to 5, then the maximum velocity of the photoelectron is: a) 2×10 6m/s b) 4×10 6 m/s c) 5×10 6m/s d) 10×10 6m/s

Answer 1

For a certain metal, b is equal to v0 and electrons come out with a maximum velocity of 4×10⁶ meters per second, the maximum velocity of the photoelectron is approximately C. 5 x 10⁶ m/s.

Step-by-step explanation:

The maximum velocity of the photoelectron can be calculated using the equation:

v = (2 * (b ²) * e * V0 / m) ^ (1/2)

where

v is the maximum velocity of the photoelectron

b is equal to v0

e is the charge of an electron (1.6 x 10⁻¹⁹ C)

V0 is the binding energy (2.71 eV)

m is the mass of an electron (9.1 x 10⁻³¹ kg).

Substituting the given values into the equation, we obtain:

v = (2 * (4 * 10⁶ m/s. m/s)² * (1.6 x 10⁻¹⁹ C) * (2.71 eV)) ^ (1/2)

After calculating the expression, the maximum velocity of the photoelectron is approximately 5 x 10⁶ m/s.

Therefore the correct answer is C. 5 x 10⁶ m/s.