Question

A ray of light emanating from the point source P(i-3j+2k) and traveling parallel to the line is incident on the plane at the point. After reflection from the plane, the ray travels along the line. It is also known that the incident ray, reflected ray, and the normal to the plane at the point of incident are in the same vector equation of the line. What is the equation of the line? a) i-3j+2k = ta + b b) i-3j+2k = λn c) i-3j+2k = sk + rr d) i-3j+2k = c_c

Answer 1

The equation representing the light path reflecting off a surface is i-3j+2k = λn, based on the law of reflection which is integral to geometric optics.The correct option is: b) i-3j+2k = λn

Step-by-step explanation:

The correct equation of the line that describes the path of light emanating from point source P(i-3j+2k) and reflecting off the surface is i-3j+2k = λn, where λ represents a scalar multiple, and n is the vector representing the normal to the plane. This equation comes from the law of reflection, which states that the incident ray, reflected ray, and normal to the reflecting surface at the point of incident all lie in the same plane, and the angle of incidence is equal to the angle of reflection.

This is part of geometric optics, studying light as rays that travel in straight lines, which can be reflected from mirrors following specific rules based on the shape of the mirror and the rays' direction of travel relative to the mirror's optical axis.The correct option is: b) i-3j+2k = λn