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Find the zero of Q(x)=10x^2-3x-4

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Answer:

10x²-3x-4=0

we write -3x as a difference

10x²+5x-8x-4=0

factor 5x into 10x²+5x =5x(2x+1)

factor -4 into -8x-4 =-4(2x+1)

we write the equation

5x(2x+1)-4(2x+1)=0

factor

(2x+1)(5x-4)=0

solve the zero product equation

2x+1=0⇔2x=-1⇔x=-1/2

5x-4=0⇔5x=4⇔x=4/5

x= -1/2 ou 5/4 Q(x)=0

User Julien Bodin
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