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What mass of potassium iodide, KI, is needed to prepare 5.60 L of a 0.255 M

User Klesun
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1 Answer

3 votes

Answer:


\huge{ \boxed{237.05 \: g}}

Step-by-step explanation:

The mass of KI required can be found by using the formula:

m = c × M × v

where:

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

m is the mass in grams

M is the molar mass in g/mol

From the question:

c = 0.255 M

v = 5.60 L

Molar mass( M) of KI = 166 g/mol


\therefore \: m = 0.255 * 166 * 5.6 \\ = 237.05 \: g

User Alex Soto
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