2 Answers

Michelle Ashwini · Answer 1 · 2024-03-20T09:59:18+0000

Answer:

Explanation:

THEOREM: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the

circle is equal to half the difference of the measures of the intercepted arcs

$O\ is \ the\ center\ of\ the\ circle\\m\ \angle{AOC}=160^o\\m\ \angle{EOF}=80^o\\\\\\m\ \angle{ABC}=(160^o-80^o)/(2)=40 ^o\\\\$

Roshane · Answer 2 · 2024-03-22T10:43:40+0000

Answer:

∠ ABC = 40°

Explanation:

the secant- secant angle ABC is half the difference of the measures of the intercepted arcs , that is

∠ ABC =
(1)/(2) ( arc ADC - EF ) =
(1)/(2) (160 - 80)° =
(1)/(2) × 80° = 40°

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