Question

On New Year's Eve, the probability of a person having a car accident is 0.08. The probability of a person driving while intoxicated is 0.28, and the probability of a person having a car accident while intoxicated is 0.04. What is the probability of a person driving while intoxicated or having a car accident ? A.0.15 B.0.16 C.0.18 D.0.32

Answer 1

D. 0.32

Step-by-step explanation:

The probability of a person driving while intoxicated or having a car accident can be calculated as:

`P=P(\text{Intoxicated)}+P(\text{ Accident) - P(Intoxicated and Accident)}`

So, replacing P(Intoxicated) = 0.28, P(Accident) = 0.08 and P(Intoxicated and Accident) = 0.04, we get

`\begin{gathered} P=0.28+0.08-0.04 \\ P=0.32 \end{gathered}`

Therefore, the answer is

D. 0.32