Question

Write an equation of the form y = mx for the line shown below. If appropriate,use the decimal form for the slope.(4,3)

Answer 1

Step 1 :

In this question, we are expected to find the equation of the line,

y = m x + c

where y = dependent variable,

x = dependent variable,

m = gradient of the line

c = intercept on the y - axis.

Step 2 :

We are given that :

`\begin{gathered} \text{The gradient of the line, } \\ m\text{ }=\text{ }\frac{y_2-y_1}{x_{2_{}}-x_1} \\ \text{where (x }_{1\text{ , }}y_{1\text{ }}\text{ ) = ( 4, 3)} \\ (x_{2\text{ , }}y_2\text{ ) = ( -4 ,- 3 )} \\ \text{Then we have that :} \\ m\text{ = }\frac{(\text{ -3 - 3 ) }}{-\text{ 4 - 4}} \\ m\text{ = }(-6)/(-8) \\ m\text{ =}(3)/(4) \end{gathered}`

Step 3 :

Since ( x 1, y 1) = ( 4, 3 ) and

CONCLUSION:

The final answer is :

`y=\text{ }(3)/(4)\text{ x }`