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Can you solve question 10a and 10b?

Can you solve question 10a and 10b?-example-1

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a. The value of a and b are 159 and 636, respectively. Thus, there are 159 animals in the 3-5 kg class interval and 636 animals in the 33-44 kg class interval.

b. An estimate of the lower boundary of the masses of the heaviest 50% of animals would be approximately 9 kg.

How to finding the values of a and b

Let x be the number of animals in the 3-5 kg class interval.

We know that the histogram has four columns of equal height, so there are 4x animals in the 33-44 kg class interval.

We also know that there are a total of 2226 animals treated at the clinic. This can be expressed as:

x + 371 + 1060 + 4x = 2226

Combining like terms

5x = 795

Dividing both sides by 5

x = 159

Therefore, there are 159 animals in the 3-5 kg class interval and 4x = 636 animals in the 33-44 kg class interval.

The table now looks like this:

Mass (kg) No. animals

3-5 159

6-12 371

13-32 1060

33-44 636

To show that a total of 2226 animals were treated

2226 - (159 + 371 + 1060 + 636) = 0

To calculate an estimate of the lower boundary of the masses of the heaviest 50% of these animals, find the class interval that represents the lower boundary of the masses for the heaviest 50% of animals.

The heaviest 50% of animals would correspond to the class interval with the highest masses.

From the given histogram, the class interval with the highest masses is 6-12.

To estimate the lower boundary of this class interval, we take the midpoint of the interval, which is (6 + 12) / 2 = 9 kg.

Therefore, an estimate of the lower boundary of the masses of the heaviest 50% of animals would be approximately 9 kg.

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