The balanced equation under acidic conditions is 3 I2 + 5 HNO3 + 6 IO3- --> 5 NO + 6 IO4- + 3 H+. Water appears as a reactant with a coefficient of 8. 8 electrons are transferred in this reaction.
The balanced equation for the reaction under acidic conditions is:
3 I2 + 5 HNO3 + 6 IO3- --> 5 NO + 6 IO4- + 3 H+
Water appears as a reactant in the balanced equation with a coefficient of 8. The equation is:
8 H2O
A total of 8 electrons are transferred in this reaction.
The complete question is- When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? 3I2 + 5 HNO3 + 6 IO3- --> 5 NO + 6 IO4- + 3 H+
Water appears in the balanced equation as a reactant, product, neither) with a coefficient of.(Enter 0 for neither.) How many electrons are transferred in this reaction?