Answer: she has five more quarters than dimes
Step-by- to this is a good example of how to get this answer find out how many more quarters than dimes Vilma has, we can start by setting up a system of equations based on the given information. Let's say Vilma has x number of dimes and y number of quarters. Since we know that she has a total of 9 coins, we can write the equation: x + y = 9 (Equation 1) Next, we know that the total value of all the coins is $1.95. The value of a dime is $0.10 and the value of a quarter is $0.25. So, we can write another equation for the total value: 0.10x + 0.25y = 1.95 (Equation 2) Now, we have a system of equations (Equation 1 and Equation 2) that we can solve to find the values of x and y. To solve the system, we can use the method of substitution or elimination. I will use the method of elimination to solve the system: Multiply Equation 1 by 0.10 to make the coefficients of x in both equations the same: 0.10(x + y) = 0.10(9) 0.10x + 0.10y = 0.90 (Equation 3) Now, we can subtract Equation 3 from Equation 2 to eliminate the x term: (0.10x + 0.25y) - (0.10x + 0.10y) = 1.95 - 0.90 0.15y = 1.05 y = 1.05 / 0.15 y = 7 Now, substitute the value of y into Equation 1 to find x: x + 7 = 9 x = 9 - 7 x = 2 Therefore, Vilma has 2 dimes and 7 quarters. To find out how many more quarters than dimes she has, we subtract the number of dimes from the number of quarters: 7 - 2 = 5