Answer:
...coefficients: a=1 ; b=-1 ; c=-20
Δ=b²−4ac=(-1)²-4(1*-20)=81
Δ is strictly positive, so the equation x²-x-20=0 has two solutions.
(-b-√Δ)/2a =(1-9)/2=-4
(-b+√Δ)/2a = (1+9)/2=5
solutions to the quadratic equation x²-x-20 = 0 :
x = 5 and x = -4.