Question

If the concentration of a solution in test tube #1 is 16 mg / mL and a serial dilution is performed with a tube dilution of 1/4 for all subsequent tubes, what is the final concentration of the solution in test tube #3?

Answer 1

Answer: You have not given the dilution ratio. Based on the information you have given here the answer is .25 mg/mL.

Explanation: The dilution factor or the dilution is the initial volume divided by the final volume.

DF=Vi/Vf - but three times (three test tubes)

Your dilution factor is 1/4 X 1/4 X 1/4 = 1/64

1/64 X 16mg/mL = 16/64 mg/mL or 1/4 mg/mL