Answer:
Therefore, after replenishing the hay at the end of the fifth day, the hayride operators will have used a total of 20 - (1 7/8) = 18 1/8 bales of hay on the three flatbeds.
Explanation:
Initially, each flatbed has 20 bales of hay. At the end of each day, they replace half of the hay on each flatbed.
After the first day, each flatbed will have 20 x (1/2) = 10 bales of hay remaining.
After the second day, each flatbed will have 10 x (1/2) = 5 bales of hay remaining.
This pattern continues, halving the amount of hay each day.
After the fifth day, each flatbed will have 20 x (1/2)^5 = 20 x (1/32) = 20/32 = 5/8 bales of hay remaining.
Since there are three flatbeds, the total number of bales of hay remaining on the three flatbeds will be:
(5/8) x 3 = 15/8 = 1 7/8 bales of hay