Find the 41st term in the given arithmetic sequence: 12, 19, 26,...

asked Sep 28, 2024 98.9k views

5 votes

by Nonna

7.8k points

Please log in or register to add a comment.

7 votes

Answer:

292

Explanation:

The first term of the AP is 12 and the common difference is 19-12=7

The 41 th term is:

$u_(41)=u_1+40*7=12+280=292\\$

Pratik Bhatt answered Oct 3, 2024

8.4k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.3m questions

11.9m answers