Question

A rectangle has a length of 12.6 ft and a perimeter of 46 ft. Find the width of the rectangle ?

Answer 1

10.4 ft

Explanation:

Given:

l = 12.6 ft

perimeter = 46 ft

`\boxed{perimeter=2*(l+w)}`

`46 = 2*(12.6+w)`

`12.6+w=46/2`

`w=23-12.6`

`=10.4\ ft`