Question

The speed of the carousel, in revolutions per minute, is 0.50 less than 0.34 of the speed of the scrambler. If the carousel travels at a speed of 3.8 revolutions per minute, how fast does the scrambler move? Round to the nearest tenth, if needed. A) s=1.1 revolutions per minute B) s=1.5 revolutions per minute C) s=9 7 revolutions per minute D) s=12.6 revolutions per minute

Answer 1

Explanation:

Let's denote the speed of the scrambler as

�

s revolutions per minute.

The speed of the carousel is given as 0.34 times the speed of the scrambler minus 0.50:

Carousel speed

=

0.34

�

−

0.50

Carousel speed=0.34s−0.50

The problem also states that the carousel's speed is 3.8 revolutions per minute, so we can set up the equation:

3.8

=

0.34

�

−

0.50

3.8=0.34s−0.50

Now, let's solve for

�

s:

0.34

�

=

4.3

0.34s=4.3

�

=

4.3

0.34

s=

0.34

4.3

�

≈

12.647

s≈12.647

Rounding to the nearest tenth, the speed of the scrambler is approximately

�

≈

12.6

s≈12.6 revolutions per minute.

So, the correct answer is D)

�

=

12.6

s=12.6 revolutions per minute