Question

DCF = FB and AE = EBCB = 38 and AB = 22DE = [?]EBFLLEnter

Answer 1

Given

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

To find the length of DE.

Step-by-step explanation:

It is given that,

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

That implies,

By using midpoint theorem of triangle, we have,

`DE=(1)/(2)BC`

Therefore,

`\begin{gathered} DE=(1)/(2)*38 \\ =19 \end{gathered}`