Question

In the diagram of ABCD shown below, BA is drawn from vertex B to point A on DC, such that BC & BA.DAСa.In AABD, mZD = 30° and mZDAB = 120°. Find the measure of all angles.b.What kind of triangle is AABD? Explain.hat kind of triangle is ADBC? Explain.

Answer 1

We have that BC = BA and m

We will have that the angle DAB and BAC are supplementary, therefore:

DAB + BAC = 180°

And replecing the value of DAB, we will get:

120 + BAC = 180 => BAC = 60.

By theorem the angles that oppose equal sides are equal, therefore: ACB = 60.

From this, we will also get that ABC = 60.

And B = 90.

Triangle ABD will be a scalene triangle.

Triangle DBC will be a rectangle triangle.