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Pls help with the part b

Pls help with the part b-example-1

1 Answer

6 votes

Answer:

x = {35.26°, 90°, 144.74°}

Explanation:

You want the solution to (1-cos(4x)+sin(4x))/(1+cos(4x)+sin(4x)) = 3sin(2x) making use of the given identity.

Rewrite

Using the given identity with θ = 2x, the equation becomes ...

tan(2x) = 3·sin(2x)

sin(2x)/cos(2x) = 3·sin(2x)

sin(2x)(1/cos(2x) -3) = 0

The zero product rule tells us the solutions are ...

sin(2x) = 0 ⇒ x = 90°

cos(2x) = 1/3 ⇒ x ≈ 35.26° or 144.74°

Solutions are x ∈ {35.26°, 90°, 144.74°}.

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Additional comment

In the open interval (0, 180°), sin(2x) is 0 only for 2x = 180°, or x = 90°.

The inverse cosine of 1/3 is ±70.529°. The negative angle is an alias of 360° -70.529°. Then 2x = {70.529° or 289.471°}, giving the above result for x.

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Pls help with the part b-example-1
User Phil Jollans
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