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Gas Laws Fact Sheet

Ideal gas law
Ideal gas constant
Standard atmospheric pressure
Caleine to Kahvin convereinn
5
The temperature of the lightbulb was
PV = nRT
R= 8.314 P
mol K
or
R = 0.0821
K
L atm
mol K
Type the correct answer in the box. Express your answer to three significant figures.
A 75.0-milliliter lightbulb is filled with neon. There are 7.16 x 104 moles of gas in it, and the absolute pressure is 116.8 kilopascals after the bulb has
been on for an hour. How hot did the bulb get?
1 atm = 101.3 kPa
K−6+272 15

User M Miller
by
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1 Answer

5 votes

Answer:

To find the temperature (T) using the ideal gas law (PV = nRT), you can rearrange the equation to solve for T:

\[T = \frac{{PV}}{{nR}}\]

Given:

\[P = 116.8 \, \text{kPa}\]

\[V = 75.0 \, \text{mL} = 0.075 \, \text{L} \, (\text{converted from milliliters})\]

\[n = 7.16 \times 10^4 \, \text{moles}\]

\[R = 8.314 \, \text{L} \, \text{kPa}^{-1} \, \text{mol}^{-1} \, \text{K}^{-1}\]

Plug in these values to find the temperature in Kelvin (K). Remember to convert kilopascals to pascals (1 kPa = 1000 Pa).

\[T = \frac{{(116.8 \times 1000) \times 0.075}}{{7.16 \times 10^4 \times 8.314}}\]

Calculate this expression to find the temperature in Kelvin.

User Hui Liu
by
7.8k points