Final answer:
To find the number of grams of Ni(OH)2 formed, calculate the moles of NaOH used. Then, use the mole ratio to find the moles of Ni(OH)2 and convert it to grams.
Step-by-step explanation:
To find the number of grams of Ni(OH)2 formed, we first need to calculate the number of moles of NaOH used in the reaction. We can use the equation:
NaOH + NiCl2 -> Ni(OH)2 + NaCl
The balanced equation tells us that the mole ratio of NaOH to Ni(OH)2 is 2:1. So, if we find the number of moles of NaOH, we can then find the number of moles of Ni(OH)2 and convert it to grams.
Given volume of NaOH solution = 20.0 mL and its concentration = 0.550 M, we can use the formula:
Molarity (M) = moles of solute / volume of solution (L)
20.0 mL is equivalent to 0.0200 L. Plugging in the values, we can solve for moles of NaOH:
0.550 M = moles NaOH / 0.0200 L
moles NaOH = 0.550 M x 0.0200 L = 0.0110 moles
Since the mole ratio of NaOH to Ni(OH)2 is 2:1, we have 0.0110 moles of Ni(OH)2 as well.
The molar mass of Ni(OH)2 is 92.71 g/mol. Multiplying the number of moles by the molar mass, we can find the mass in grams:
mass = 0.0110 moles x 92.71 g/mol = 1.0198 g
Therefore, 1.02 grams of solid Ni(OH)2 are formed in the reaction.
Learn more about calculating grams of Ni(OH)2 formed in a chemical reaction