Answer:
To decide the moles of sodium phosphate expected to respond totally with calcium chloride, you first need to compose the reasonable compound condition for the response between sodium phosphate (\(Na_3PO_4\)) and calcium chloride (\(CaCl_2\)).
The reasonable compound condition is:
\[3Na_3PO_4 + 2CaCl_2 \rightarrow Ca_3(PO_4)_2 + 6NaCl\]
This condition shows a 1:2 molar proportion between sodium phosphate and calcium chloride.
Presently, how about we compute the moles of calcium chloride (\(CaCl_2\)) given 45 grams. The molar mass of \(CaCl_2\) is around 110.98 g/mol.
\[ \text{Moles of } CaCl_2 = \frac{\text{Mass}}{\text{Molar mass}} = \frac{45 \, \text{g}}{110.98 \, \text{g/mol}} \]
When you track down the moles of \(CaCl_2\), you can utilize the molar proportion from the reasonable condition to decide the moles of \(Na_3PO_4\). For this situation, you'll require two times as numerous moles of \(Na_3PO_4\).
Remember that this expects total response and that every one of the reactants are in the right stoichiometric extents.