235,677 views
17 votes
17 votes
Please help :( It’s my study guide for my upcoming test

Please help :( It’s my study guide for my upcoming test-example-1
User Rj Tubera
by
2.6k points

1 Answer

14 votes
14 votes

Let x the number of quartes and y the number of nickels

So (1) x + y = 47

Solve for x

x = 47 - y

Then .25x +.05 =4.95

It is better if you multiply both sides by 100 to get rid of the decimal

100(.25x +.05) = 100(4.95)

(2) 25x + 5y = 495

Replace the first x value in the second equation

(2) 25x + 5y = 495

25(47 - y ) + 5y = 495

Then solve the equation for y

1175 - 25y + 5y = 495

-25y + 5y = 495 - 1175

-20y = -680

y = -680/ -20

y = 34 nickels

Replace this y value in the x equation

x = 47 - y

x = 47 - 34

x = 13 quarters

User Sosytee
by
2.9k points