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Suppose that f(x)=x^2-4x-5 a. What is the vertex of f

User Orch
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1 Answer

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To find the vertex you take half of the middle term and make it negative.
-4x is our middle term half of it is -2 and making it negative makes it +2

2 is our x value of the vertex
next you plug in 2 into the equation
2^2 -8 -5
4-8-5 = -9

Vertex is (2,-9)

Another way is a calculus way which is to take the derivative and set it equal to 0 then solve for x, to get your x value.
Suppose that f(x)=x^2-4x-5 a. What is the vertex of f-example-1
User MnZrK
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