Question

A bowl has 4 green marbles 3 red marbles and 2yellow marbles what is the probability that you are going to select a red marble and a yellow marble. You replace the marble before another marble is selected

Answer 1

2/27

Step-by-step explanation

There are a total of 9 marbles in the bowl. The probability of drawing a red marble is,

`P(red)=(\#red.marbles)/(\#total.marbles)=(3)/(9)=(1)/(3)`

Then you draw another marble, but you put the first back in the bowl, so the total number of marbles is the same. The probability of drawing a yellow marble is,

`P(yellow)=(\#yellow.marbles)/(\#total.marbles)=(2)/(9)`

The probability of drawing a red marble and a yellow marble is,

`P(red.and.yellow)=P(red)\cdot P(yellow)=(1)/(3)\cdot(2)/(9)=(2)/(27)`