Question

Suppose logex = 3, log y = 7, and logz= -2.Find the value of the following expression.loga42

Answer 1

`\begin{gathered} \log _ax=3 \\ \log _ay=7 \\ \log _az=-2 \end{gathered}`

Therefore,

`\begin{gathered} \log _ax^3+\log _ay-\log _az^4=\log _a((x^3y)/(z^4)) \\ 3\log _ax^{}+\log _ay-4\log _az=3(3)+7-4(-2)=9+7-8=8 \end{gathered}`