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A boat travels 10 miles down river in the same time that it can travel 8 miles up river.

If the current of the river is 1.8 mph, what proportion below can be used to solve for
the speed of the boat in still water?

User Olokoo
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1 Answer

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Final answer:

The speed of the boat in still water can be solved by setting up an equation using the distances traveled up and down the river.


Step-by-step explanation:

Let's denote the speed of the boat in still water as x mph.

When the boat travels down the river, the effective speed will be the sum of the boat's speed and the speed of the current. So, the effective speed is (x + 1.8) mph.

When the boat travels up the river, the effective speed will be the difference between the boat's speed and the speed of the current. So, the effective speed is (x - 1.8) mph.

According to the given information, the time taken to travel 10 miles down the river is the same as the time taken to travel 8 miles up the river. Using the formula Distance = Speed x Time, we can set up the following equation:

10/(x + 1.8) = 8/(x - 1.8)

To solve for x, we can cross multiply and simplify the equation:

10(x - 1.8) = 8(x + 1.8)

10x - 18 = 8x + 14.4

2x = 32.4

x = 16.2

The speed of the boat in still water is 16.2 mph.


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User DMCS
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