Question

What is the equation of the line that passes through the point (3, -8) and has a slope of

Answer 1

`y= 4(x-3)+8`

Explanation:

your question is incomplete. you have not written the value of the slope.

How ever i can give you a methodology of the question by simply letting slop =4

General formula for equation of line is

y - y1 = m ( x- x1 ) ;

where (x1,y1) is know point in our case its (3,8)

m is the slop in our case m=4, (x,y) is the general point of the required line

so our equation become

y-8=4(x-3)

y= 4(x-3)+8