Question

3

What is the upthrust on a body which displaces
0.6 m³ of water, 0.5 m3 of methylated spirit?
(density of water = 103 kgm-3, density of

Answer 1

The upthrust on a body in water and methylated spirit is equal to the weight of the fluid it displaces.

Step-by-step explanation:

The upthrust on a body is equal to the weight of the fluid it displaces. In this case, we need to calculate the upthrust for both water and methylated spirit.

For water, the density is 103 kg/m³, so the weight of 0.6 m³ of water is:

Weight of water = density of water × volume of water = 103 kg/m³ × 0.6 m³ = 61.8 kg

Therefore, the upthrust on the body in water is 61.8 kg.

Similarly, for methylated spirit, the density is given and the volume is given as 0.5 m³. Therefore, the upthrust on the body in methylated spirit is:

Weight of methylated spirit = density of methylated spirit × volume of methylated spirit

Learn more about Upthrust in fluids