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What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (2, -1)? a) y = -1/3x - 1/3 b) y = -1/3x - 5/3 c) y = 3x - 3 d) y = 3x - 7

User Mark Adams
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1 Answer

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Final answer:

The equation of the line that is perpendicular to the given line and passes through the point (2, -1) is y = -1/3x - 1/3, which is option (a).

Step-by-step explanation:

The question involves finding the equation of a perpendicular line in slope-intercept form that passes through a given point. Since the original line has a slope of 3, as per the slope-intercept form equation y = mx + b, where m is the slope, the perpendicular line will have a negative reciprocal slope, which is -1/3. Using the point (2, -1) to solve for the y-intercept, we calculate:

y = mx + b

-1 = (-1/3)(2) + b

-1 = -2/3 + b

b = -1 + 2/3

b = -3/3 + 2/3

b = -1/3

So the equation in slope-intercept form is y = -1/3x - 1/3, which corresponds to option (a).

User Luanjot
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