Question

A line has the equationFind the equation of a parallelline passing through (3,2).Y=1/3x-5

Answer 1

y = 1/3x + 1

Step-by-step explanation:

The equation of a line with slope m that passes through the point (x1, y1) can be founded using the following:

`y-y_1=m(x-x_1)`

If the line is parallel to y = 1/3x - 5, the line will have the same slope. Since the slope of y = 1/3x - 5 is 1/3 because it is the value beside the x, the slope of our line is also 1/3

Then, replacing m by 1/3 and (x1, y1) by (3, 2), we get:

`y-2=(1)/(3)(x-3)`

Finally, solve for y:

`\begin{gathered} y-2=(1)/(3)(x)-(1)/(3)(3) \\ y-2=(1)/(3)x-1 \\ y-2+2=(1)/(3)x-1+2 \\ y=(1)/(3)x+1 \end{gathered}`

Therefore, the equation of the line is:

y = 1/3x + 1