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Write a quadratic function whose zeros are 2 and 12

User Theowi
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1 Answer

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If one root is
x_(1)=2, then one term should be as follows:


  • (x-2)

Similarly, the other root would be:


  • (x-12)

If we multiply these two terms, we obtain a second-degree equation:


  • (x-2)(x-12)=0

If we expand this, we get:


  • (x-2)(x-12)=x^2-12x-2x+24

  • =x^2-14x+24
User Dkatzel
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