Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

asked Jun 12, 2024 152k views

1 vote

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3 votes

Answer:

$\sf\\1.\ Solution:\\\\x=(6\pm√(-144))/(2)=(6)/(2)\pm(12i)/(2)=3\pm6i$

$\sf\\2.\ Solution:\\(4-3i)-5(-2+7i)+(8+7i)\\=4-3i+10-35i+8+7i\\=22-31i$

$\sf\\3.\ (3-√(-49))^2\\=(3-7i)^2 \\=3^2 -2(3)(7i)+(7i)^2\\=9-42i-7^2\\=-40-42i$

$\sf\\4.\ (8+9i)(2-i)-(1-i)(1+i)\\=8(2-i)+9i(2-i)-(1-i^2)\\=16-8i+18i-9i^2-(1+1)\\=16-8i+18i+9-2\\=23+10i$

Lameek answered Jun 16, 2024

7.8k points

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