Final answer:
The power of lens required to correct the hypermetropic eye is 1 diopter.
Step-by-step explanation:
The near point of a hypermetropic eye is the closest point at which a person with hypermetropia (farsightedness) can see objects clearly without straining their eyes. In this case, the near point is given as 1 m. On the other hand, the near point of a normal eye is typically around 25 cm.
To correct the hypermetropic eye, a converging lens (convex lens) is needed. The power of the lens required can be calculated using the formula:
Power of lens = 1 / Near point (in meters)
Using the given near point of 1 m, the power of lens required to correct this defect would be:
Power of lens = 1 / 1 = 1 diopter
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