Question

Find the zeros of f(x) = 7x² + 42.
The zeros are x =
and x =

Answer 1

To find the zeros of the function f(x) = 7x² + 42, we set f(x) = 0 and solve for x. The solutions are complex numbers: x = ±i√(6).

Step-by-step explanation:

To find the zeros of the function f(x) = 7x² + 42, we set f(x) = 0 and solve for x.

7x² + 42 = 0

Dividing both sides by 7, we get:

x² + 6 = 0

Subtracting 6 from both sides:

x² = -6

Taking the square root of both sides:

x = ±√(-6)

Since we cannot take the square root of a negative number in real numbers, there are no real zeros for this function. The solutions are complex numbers: x = ±i√(6).

Learn more about Finding zeros of a quadratic function