Answer:
In the G1 phase, a meiocyte has 40 chromosomes and 40 pg (picograms) of DNA. The number of chromosomes and the amount of DNA in a gamete can be determined by considering the process of meiosis.
During meiosis, a meiocyte undergoes two rounds of cell division, resulting in the formation of four haploid gametes. Each round of division involves the separation of homologous chromosomes, resulting in a reduction in chromosome number.
In the first round of meiotic division (Meiosis I), homologous chromosomes separate, resulting in two daughter cells. Each daughter cell contains half the number of chromosomes as the parent cell. Therefore, in this case, each daughter cell would have 40/2 = 20 chromosomes.
In the second round of meiotic division (Meiosis II), the sister chromatids of each chromosome separate, resulting in the formation of four haploid gametes. Each gamete contains a single set of chromosomes. Therefore, in this case, each gamete would have 20 chromosomes.
The amount of DNA in the gametes remains the same as in the parent cell, as DNA replication occurs only once during the S phase of the cell cycle. Therefore, each gamete would still contain 40 pg of DNA.
To summarize:
- The number of chromosomes in the gamete would be 20.
- The amount of DNA in the gamete would be 40 pg.
Step-by-step explanation: