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How many joules of energy are needed to raise the temperature of 250 grams of water from 45°C to 85°C? The specific heat for liquid water is C= 4.18 J/g°C.

User Flyersun
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1 Answer

5 votes

Step-by-step explanation:

250 g * (85-45 C) * 4.18 J / (g C) = 41800 J

See how the 'g' and the 'C' cancel and you are left with 'J' for the answer?

User Mohammed Riyadh
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