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Solve by factoring

2x^2 -x-3=0

2 Answers

2 votes

Answer: x₁=-1 x₂=1.5

Explanation:


2x^2-x-3=0\\\\2x^2+(2x-3x)-3=0\\\\2x^2+2x-3x-3=0\\\\2x*(x+1)-3*(x+1)=0\\\\(x+1)*(2x-3)=0\\\\x+1=0\\\\x_1=-1\\\\2x-3=0\\\\2x=3\\\\Divide \ both\ sides \ of \ the \ equation\ by \ 2:\\\\x_2=1.5

6 votes

Answer:

See explanation

Explanation:

2x^2-x-3=0

(2x^2+2x)(-3x-3)
2x(x+1)-3(x+1)
(2x-3)(x+1)=0

x=3/2 and x=-1

User Dimitri Acosta
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